Y=-1/2x^2+4x+1

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Solution for Y=-1/2x^2+4x+1 equation:


x in (-oo:+oo)

Y = (-1/2)*x^2+4*x+1 // - (-1/2)*x^2+4*x+1

Y-((-1/2)*x^2)-(4*x)-1 = 0

Y+(1/2)*x^2-4*x-1 = 0

Y+1/2*x^2-4*x-1 = 0

DELTA = (-4)^2-(1/2*4*(Y-1))

DELTA = 16-2*(Y-1)

16-2*(Y-1) = 0

16-2*(Y-1) = 0

18-2*Y = 0

18-2*Y = 0

18-2*Y = 0 // - 18

-2*Y = -18 // : -2

Y = -18/(-2)

Y = 9

DELTA = 0 <=> t_1 = 9

x = 4/(1/2*2) i Y = 9

x = 4 i Y = 9

( x = ((16-2*(Y-1))^(1/2)+4)/(1/2*2) or x = (4-(16-2*(Y-1))^(1/2))/(1/2*2) ) i Y > 9

( x = (16-2*(Y-1))^(1/2)+4 or x = 4-(16-2*(Y-1))^(1/2) ) i Y > 9

Y-9 > 0

Y-9 > 0 // + 9

Y > 9

x in { 4, (16-2*(Y-1))^(1/2)+4, 4-(16-2*(Y-1))^(1/2) }

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